In a pseudo first order hydrolysis of ester i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The average rate of reaction is calculated using the formula:Average rate $= -\frac{\Delta[Ester]}{\Delta t}$Given the concentration of ester at $

Vedclass · Accepted Answer

$4.67 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}$

Vedclass · Answer

(B) The average rate of reaction is calculated using the formula:Average rate $= -\frac{\Delta[Ester]}{\Delta t}$Given the concentration of ester at $t = 30 \, s$ is $0.31 \, mol \, L^{-1}$ and at $t = 60 \, s$ is $0.17 \, mol \, L^{-1}$.Average rate $= -\frac{0.17 - 0.31}{60 - 30} \, mol \, L^{-1} \, s^{-1}$Average rate $= \frac{0.14}{30} \, mol \, L^{-1} \, s^{-1} = 4.67 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}$.

In a pseudo first order hydrolysis of ester in water,the following results were obtained.
$t/s$ $0$ $30$ $60$ $90$
$Ester/mol\, L^{-1}$ $0.55$ $0.31$ $0.17$ $0.085$

What will be the average rate of reaction between the time interval $30$ to $60$ seconds?

Similar Questions

The joint equation of the lines passing through the origin and trisecting the first quadrant is . . . . . .

If $a, b$ and $c$ form a geometric progression with common ratio $r$,then the sum of the ordinates of the points of intersection of the line $ax + by + c = 0$ and the curve $x + 2y^2 = 0$ is

If the line joining $A(1, 3, 4)$ and $B$ is divided by the point $P(-2, 3, 5)$ in the ratio $1: 3$, then the coordinates of $B$ are:

The separation of a racemic mixture into pure enantiomers is termed as

The cell junctions called tight,adhering,and gap junctions are found in

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In a pseudo first order hydrolysis of ester in water,the following results were obtained.$t/s$$0$$30$$60$$90$$Ester/mol\, L^{-1}$$0.55$$0.31$$0.17$$0.085$What will be the average rate of reaction between the time interval $30$ to $60$ seconds?